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4x^2=-8x+221
We move all terms to the left:
4x^2-(-8x+221)=0
We get rid of parentheses
4x^2+8x-221=0
a = 4; b = 8; c = -221;
Δ = b2-4ac
Δ = 82-4·4·(-221)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-60}{2*4}=\frac{-68}{8} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+60}{2*4}=\frac{52}{8} =6+1/2 $
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